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Byju's Answer
Standard XII
Chemistry
Electrode Potential
Calculate E...
Question
Calculate
E
c
e
l
l
.
P
t
(
s
)
|
H
2
(
g
)
1
a
t
m
|
H
A
(
K
a
=
10
−
7
)
1
M
|
|
H
B
(
K
a
=
10
−
5
)
1
M
|
H
2
(
g
)
1
a
t
m
|
P
t
(
s
)
A
0.06
V
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B
0.03
V
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C
0.04
V
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D
0.05
V
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Solution
The correct option is
A
0.06
V
E
c
e
l
l
=
E
0
c
e
l
l
−
0.0591
1
log
[
H
A
]
[
H
B
]
=
0
−
0.0591
1
log
(
√
10
−
7
10
−
5
)
=
(
0.1182
v
/
2
)
=
0.0591
V
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0
Similar questions
Q.
The EMF of the cell
M
|
M
n
+
(
0.2
M
)
|
|
H
+
(
1
M
)
|
H
2
(
g
)
(
1
a
t
m
)
, Pt at
25
∘
C
is 0.81 V. Calculate the valency of the metal if the standard oxidation potential of the metal is 0.76 V.
Q.
The EMF of the cell
M
|
M
n
+
(
0.01
M
)
|
|
H
+
(
1
M
)
|
H
2
(
g
)
(
1
a
t
m
)
,
Pt at
25
o
C is
0.82
V. Calculate the valency of the metal if the standard oxidation potential of the metal is
0.76
V.
Take
2.303
R
T
F
=
0.06
at
25
o
C.
Q.
At
25
∘
C
,
Δ
H
f
(
H
2
O
,
I
)
=
−
56700
J
/
m
o
l
and energy of ionization of
H
2
O
(
I
)
=
19050
J
/
m
o
l
If the reversible EMF at
25
∘
C
of the cell is
414
×
10
−
x
, then the value of x is ?
P
t
|
H
2
(
g
)
(
1
a
t
m
)
|
H
+
|
|
O
H
−
|
O
2
(
g
)
(
1
a
t
m
)
|
P
t
, if at
26
∘
C
the emf increase by 0.001158 V.
Ans in V
Q.
Calculate the e.m.f. (in V) of the cell:
P
t
|
H
2
(
g
)
|
B
O
H
(
a
q
)
|
|
H
A
(
a
q
)
|
H
2
(
g
)
|
P
t
;
(
0.1
b
a
r
;
1
M
;
0.1
M
;
1
b
a
r
Given:
K
a
(
H
A
)
=
10
−
7
,
K
b
(
B
O
H
)
=
10
−
5
Q.
For the following electrochemical cell at 298K,
P
t
(
s
)
|
H
2
(
g
,
1
b
a
r
)
|
H
+
(
a
q
,
1
M
)
|
|
M
4
+
(
a
q
)
,
M
2
+
(
a
q
)
|
P
t
(
s
)
E
c
e
l
l
=
0.092
V when
[
M
2
+
(
a
q
)
]
[
M
4
+
(
a
q
)
]
=
10
x
.
Given
:
E
0
M
4
+
/
M
2
+
=
0.151
V
;
2.303
R
T
F
=
0.059
V
The value of x is :
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