Calculate E- values of following reactions- Cus- Zn2- aq- Zns - Cu2-aq-Given- E0Cu2-Cu-0-34 V- E0Zn2-Zn-0-76 V-

$E^{0}$ for the cell, $Z n | Z n {^{2 +}}_{(a q)} | | C u {^{2 +}}_{(a q)} | C u$ is $1.10 V$ at $25^{0} C$ . The equilibrium constant for $Z n + C u {^{2 +}}_{(a q)} \to Z n {^{2 +}}_{(a q)} + C u$ the cell reaction is of the order of :

C u I (s) + e^{-} \to C u (s) + I^{-};

E_{C u^{+} / C u}^{o} = - 0.16 V

Z n^{2 +} (a q) + 2 e^{-} \to Z n (s);

E_{Z n^{2 +} / Z n}^{o} = - 0.76 V

Calculate the EMF.

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Calculate E∘ values of following reactions: Cu(s)+Zn2+(aq)→Zn(s)+Cu2+(aq)[Given: E0Cu2+/Cu=0.34V, E0Zn2+/Zn=−0.76V]

The correct option is A −1.10VE∘Cu2+/Cu=0.34V,E∘Zn2+/Zn=−0.76VCu2+(aq)+2e−→Cu(s);E∘=+0.34V ---- (1)Zn2+(aq)+2e−→Zn;E∘=−0.76V ----- (2)Inverting (1),Cu(s)→Cu2+(aq)+2e−;E∘=−0.34V ----- (3)Adding (2) and (3),Cu(s)+Zn2+(aq)→Zn(s)+Cu2+(aq)E∘=−0.76V−0.34V=−1.10V

Calculate $E^{\circ}$ values of following reactions:

$C u_{(s)} + Z n_{(a q)}^{2 +} \to Z n_{(s)} + C u_{(a q)}^{2 +}$

[Given: $E_{C u^{2 +} / C u}^{0} = 0.34 V, E_{Z n^{2 +} / Z n}^{0} = - 0.76 V$ ]