Calculate e-m-f of the following cell at 298 K- 2Cr s -3 Fe 2- 0-1M - 2 Cr 3- 0-01M -3Fe s Given- E Cr 3- -Cr -0-74V E Fe 2- -Fe -0-44V

E _ cell ^ o = E _ C ^ o E _ A ^ o = 0.44 ( 0.74) =0.3V E _ cell =0.3 0.0591 6 log[ Cr ^ 3+ ] ^ 2 [ Fe ^ 2+ ] ^ 3 ...

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Electrode Potential

Calculate e.m...

Question

Calculate e.m.f of the following cell at $298 K$ :
$2 C r (s) + 3 {F e}^{2 +} (0.1 M) \to 2 {C r}^{3 +} (0.01 M) + 3 F e (s)$
Given: $E ({C r}^{3 +} | C r) = - 0.74 V E ({F e}^{2 +} | F e) = - 0.44 V$

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Solution

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3 F e^{2 +} (a q) + 2 C r (s) = 2 C r^{3 +} (a q) + 3 F e (s)

E_{F e^{2 +} / F e}^{o} = - 0.44

E_{C r^{3 +} / C r}^{o} = - 0.74

(F = 96500 C)

C r | C r^{3 +} (0.1 M) | | F e^{2 +} (0.01 M) | F e

E_{C r^{3 +} / C r}^{\circ} = - 0.75 v o l t; E_{F e^{2 +} / F e}^{\circ} = - 0.45 v o l t)

E_{c e l l}^{\circ}

2 C r (s) + 3 F e^{2 +} (0.01 M) \to 2 C r^{3 +} (0.01 M) + 3 F e (s)

E_{c e l l} = 0.261 V

E^{\circ}

[E^{o} (F e^{2 +} / F e) = - 0.44 V]

E^{\circ} (A^{2 +} / A) = - 2.37 V

E^{\circ} (B^{2 +} / B) = - 0.14 V

E_{c e l l}^{\circ}

2 C r (s) + 3 F e^{2 +} (0.01 M) \to 2 C r^{3 +} (0.01 M) + 3 F e (s)

E_{c e l l} = 0.261 V

E^{\circ}

[E^{o} (F e^{2 +} / F e) = - 0.44 V]

E^{\circ} (A^{2 +} / A) = - 2.37 V

E^{\circ} (B^{2 +} / B) = - 0.14 V

E M F

Z n | Z n^{2 +} (0.01 M) | | C u^{2 +}] (0.1 M) | C u

298 K

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