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Question

Calculate EoCell value of the following reactions:

Zn(s)+Cu2+(aq)Zn2+(aq)+Cu(s)

[Given: ECu2+/Cu=0.34V,EZn2+/Zn=0.76V]

A
0.42V
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B
0.46V
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C
0.46V
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D
1.1V
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Solution

The correct option is C 1.1V
Given: ECu2+/Cu=0.34V,EZn2+/Zn=0.76V

Cu2+(aq)+2eCu(s);Eredn=+0.34V

Zn2+(aq)+2eZn(s);Eredn=0.76V and Eooxdn=+0.76V

In the given reaction, Cu is reduced and Zn is oxidized.

Zn(s)+Cu2+(aq)Zn2+(aq)+Cu(s)

Eo=Eooxidation+Eoreduction=0.76+0.34=1.1V

Hence, option (D) is correct.

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