Calculate EoCell value of the following reactions- Zns - Cu2- aq - Zn2-aq - Cus-Given- E-Cu2-Cu-0-34 V- E-Zn2-Zn-0-76 V-

The correct option is C #160; #160; 1.1 V Given: E^∘_Cu^2+/Cu=0.34 V, E^∘_Zn^2+/Zn= 0.76 V Cu^2+_(aq) + 2e^ → Cu_(s) ; E^∘_redn= +0.34V ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Nernst Equation

Calculate E...

Question

Calculate $E_{C e l l}^{o}$ value of the following reactions:

$Z n (s) + C u^{2 +} (a q) \to Z n^{2 +} (a q) + C u (s)$

[Given: $E_{C u^{2 +} / C u}^{\circ} = 0.34 V, E_{Z n^{2 +} / Z n}^{\circ} = - 0.76 V$ ]

- 0.42 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.46 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 0.46 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.1 V

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

Suggest Corrections

Similar questions

E^{\circ}

C u_{(s)} + Z n_{(a q)}^{2 +} \to Z n_{(s)} + C u_{(a q)}^{2 +}

E_{C u^{2 +} / C u}^{0} = 0.34 V, E_{Z n^{2 +} / Z n}^{0} = - 0.76 V

Z n (s) / Z n^{2 +} (a q) ∥ C u^{2 +} (a q) / C u (s)

{E^{0}}_{{Z n}^{2 +} / Z n} =

-

{E^{0}}_{{C u}^{2 +} / C u} =

+

{E^{0}}_{c e l l}

K

298 K

C u (s) | C u^{2 +} (1.0 M) | | A g^{+} (1.0 M) | A g (s)

E_{c e l l}^{o} = 0.46 V

Z n (s) | Z n^{2 +} (1.0 M) | | C u^{2 +} (1.0 M) | C u (s)

E_{c e l l}^{o} = 1.10 V

E_{c e l l}

298 K

Z n (s) | Z n^{2 +} (0.1 M) | | A g^{+} (1. 0 M) | A g (s)

E^{\circ}

{Zn(s)|Zn}^{2 +} (aq) | | {Cu}^{2 +} (aq)|Cu(s)

1.10

25^{\circ} C

Zn(s) + {Cu}^{2 +} (aq) \to Cu(s) + {Zn}^{2 +} (aq)

1.94 \times 10^{x}

x

E^{\circ}

Z n | Z n^{2 +} (a q) | | C u^{2 +} (a q) | C u

25^{\circ} C

Z n + C u^{2 +} (a q) ⇌ C u + Z n^{2 +} (a q)

Join BYJU'S Learning Program