Calculate entropy change for vaporization of 1 mole of liquid water to steam at 100∘C if ΔHv=40.8 kJ mol−1.
ΔSv=109.38 JK−1 mol−1
For entropy change of vaporization can be given as, ΔSv=ΔHvT
Given values are, ΔHv=40.8×103 Jmol−1; T=373K
Therefore ΔSv=(40.8×103373)
ΔSv=109.38 JK−1 mol−1