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Entropy Change in Isothermal Process

Calculate ent...

Question

Calculate entropy change when $10$ moles of an ideal gas expands reversibly and isothermally from an initial volume of $10$ litre to $100$ litre at $300 K$ .

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Solution

$Δ S = 2.303 n R log (\frac{V_{2}}{V_{1}})$

$= 2.303 \times 10 \times 8.314 log (\frac{100}{10}) = 191.47 J K^{- 1}$

Thus $Δ S = 191.47 J K^{- 1}$

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