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Byju's Answer
Standard XII
Chemistry
Characteristics of Equilibrium Constant
Calculate equ...
Question
Calculate equilibrium constant for the equilibrium
2
m
n
O
−
4
+
6
H
+
+
5
H
2
C
2
O
4
⇌
2
M
N
2
+
+
8
H
2
O
+
10
C
O
2
Given that,
E
0
M
n
O
4
M
n
2
+
,
=
1.51
V
and
E
0
C
O
3
C
2
O
2
−
4
=
−
0.49
V
Open in App
Solution
E
o
c
e
l
l
=
E
c
a
t
h
o
d
e
−
E
a
n
o
d
e
=
1.51
+
0.49
=
2
Volts
At equilibrium
E
c
e
l
l
=
0
So
E
o
c
e
l
l
=
−
0.059
/
n
l
o
g
K
c
⇒
2
=
−
0.059
5
log
K
c
⇒
log
K
c
=
10
−
0.059
⇒
K
C
=
2.51
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0
Similar questions
Q.
Write half-reactions using electrons.
2
M
n
O
−
4
+
5
C
2
O
2
−
4
+
16
H
+
⟶
10
C
O
2
+
2
M
n
2
+
+
8
H
2
O
Q.
Classify the following reaction.
2
M
n
O
−
4
+
5
H
2
C
2
O
4
+
6
H
+
→
2
M
n
2
+
+
10
C
O
2
+
8
H
2
O
Q.
The oxidising agent in the following reaction is:
2
M
n
O
−
4
+
16
H
+
+
5
C
2
O
−
2
4
→
2
M
n
2
+
+
8
H
2
O
+
10
C
O
2
Q.
In the following reaction,
O
18
is in what?
2
M
n
O
4
−
+
5
H
2
O
18
2
+
6
H
+
→
2
M
n
2
+
+
8
H
2
O
+
5
O
2
Q.
Determine the standard equilibrium constant of the following reaction at
298
K
.
2
M
n
O
−
4
+
6
H
+
+
5
H
2
C
2
O
4
→
2
M
n
2
+
+
8
H
2
O
+
10
C
O
2
(
E
∘
c
e
l
l
=
2.0
V
)
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