Question

Calculate equivalent weight of the underlined.

$\underset{–}{CH\equiv CH}+2Na⟶NaC\equiv CNa+H_2$
(If equivalent weight is $X$, answer is $(X-10)$)

Answer 1

In the given reaction, 1 mole of acetylene reacts with two moles of sodium.
Hence, its equivalent weight will be equal to one half of its molecular weight.
Equivalent weight of acetylene = $\frac{molecularweight}{2}=\frac{26}{2}=13$