Question

Calculate formal charge of atoms $HCl{O}_4,C{O_3}^2$.

Answer 1

The formal charge on three oxygen atom has electron pair shared by chlorine,

$Cl=\frac{v-1}{2S-L}=0=\frac{6-1}{2\times 2-6}=-1$

The formal charge on the oxygen atom having an electron pair shared by chlorine and hydrogen, then the formal charge is :

$0=\frac{1-1}{2\times 2-0}=0$

Formal charge on$H$ is $0=\frac{1-1}{2\times 2-0}=0$

For the ${Co}_3^2$

For the oxygen:

$6-4-\frac{1}{2}\times 4=0$

For the carbon atom:

$4-0-\frac{1}{2}\times 8=0$

For the second oxygen:

$6-6-\frac{1}{2}\times 2=-1$