Calculate - 2-3-5-8 -4-6-7-16

The correct option is B 1643/1152 (2/3 + 5/8)× (4/6 + 7/16) = nbsp;(2× 8/3× 8 nbsp;+ 5× 3/8× 3)× (4× 8/6× 8 + 7× 3/16× 3) (Since LCM of 3 and 8 is 24 and L ...

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Standard VII

Mathematics

BODMAS

Calculate : 2...

Question

Calculate : $(\frac{2}{3} + \frac{5}{8}) \times (\frac{4}{6} + \frac{7}{16})$

$\frac{1653}{1152}$

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$\frac{1643}{1152}$

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$\frac{1743}{1152}$

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$\frac{1463}{1152}$

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Solution

The correct option is B
$\frac{1643}{1152}$

$(\frac{2}{3} + \frac{5}{8}) \times (\frac{4}{6} + \frac{7}{16})$

= $(\frac{2 \times 8}{3 \times 8} + \frac{5 \times 3}{8 \times 3}) \times (\frac{4 \times 8}{6 \times 8} + \frac{7 \times 3}{16 \times 3})$ (Since LCM of 3 and 8 is 24 and LCM of 6 and 16 is 48)

= $(\frac{16}{24} + \frac{15}{24}) \times (\frac{32}{48} + \frac{21}{48})$

= $\frac{31}{24} \times \frac{53}{48}$

= $\frac{1643}{1152}$

Suggest Corrections

Similar questions

Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$

Q. Calculate 1 − 2 + 3 − 4 + 5 − 6 + 7 − 8 + ... + 49 − 50.

Q. Find the value of:

(1) 3⁶
(2) 6³
(3) 2⁶
(4) 1⁸
(5) 5⁴
(6) 4³
(7) 10⁵
(8) 10⁷
(9) 7⁴
(10) 8²

Q. Express

{[(2^{1 / 2} . 4^{3 / 4} . 8^{5 / 6} . 16^{7 / 8} . 32^{9 / 10})^{4}]}^{8 / 25}

as an integer.

Q. Calculate:

1 − 2 + 3 − 4 + 5 − 6 +......+ 15 − 16

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Calculate : (23+58)×(46+716)

The correct option is B 16431152 (23+58)×(46+716) = (2×83×8+5×38×3)×(4×86×8+7×316×3) (Since LCM of 3 and 8 is 24 and LCM of 6 and 16 is 48) = (1624 +1524)×(3248+2148) = 3124×5348 = 16431152

Calculate : $(\frac{2}{3} + \frac{5}{8}) \times (\frac{4}{6} + \frac{7}{16})$