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Real Gases

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Question

Calculate from the Van der Waals equation, the temperature at which $192 g$ of $S O_{2}$ would occupy a volume of $6 d m^{3}$ at $15 a t m$ pressure
$[a = 5.68 a t m L^{2} m o l^{- 2}, b = 0.06 L m o l^{- 1}]$

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Solution

$[P + \frac{a \times n^{2}}{V^{2}}] [V - n b] = n R T$
$[15 + \frac{5.68 \times 9}{36}] [6 - 3 \times .06] = 3 \times 8.314 \times T$
$T = 38. K$

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