Calculate hte number of moles of :
(a) $C O_{2}$ which contain 8.00 g of $O_{2}$
(b)methane in 0.80 g of methane.

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Solution

(a) 1 mole of $C O_{2}$ contains $O_{2}$ = 32g
So, $C O_{2}$ having 8 gm of $O_{2}$ has no. of moles = $\frac{8}{32}$ = 0.25 moles
(b) 16 g of methane has no. of moles = 1
So, 0.80 g of methane has no. of moles = $\frac{0.8}{16}$ = 0.05 moles

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