Calculate (i) effective resistance (ii) current (iii) Potential difference across 10 resistor of a circuit shown in the figure.

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Solution

All resistance are connected in parallel across 2 V batteries,
So,
(i) Effective resistance $= 5 Ω + 10 Ω$
$R_{e f f} = 15 Ω$

(ii) Current $\Rightarrow i = \frac{V}{R_{e f f}} = \frac{2}{15} a m p$

(iii) Potential across $10 Ω \Rightarrow V = I R = \frac{2}{15} \times 10 = \frac{4 V}{3}$

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Calculate (i) effective resistance (ii) current (iii) Potential difference across 10 resistor of a circuit shown in the figure.

All resistance are connected in parallel across 2 V batteries, So,(i) Effective resistance =5Ω+10Ω Reff=15Ω(ii) Current ⇒i=VReff=215amp(iii) Potential across 10Ω⇒V=IR=215×10=4V3

All resistance are connected in parallel across 2 V batteries,
So,
(i) Effective resistance $= 5 Ω + 10 Ω$
$R_{e f f} = 15 Ω$

(ii) Current $\Rightarrow i = \frac{V}{R_{e f f}} = \frac{2}{15} a m p$

(iii) Potential across $10 Ω \Rightarrow V = I R = \frac{2}{15} \times 10 = \frac{4 V}{3}$