Calculate (i) the number of moles (ii) the number of molecules in 294 g of sulphuric acid.
[ $S = 32, H = 1, O = 16$ ]

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Solution

Gram molecular weight of $H_{2} S O_{4} = 98 g$
Given weight= $294 g$
(i) No. of moles= $\frac{Given weight}{Gram molecular weight} = \frac{294}{98} = 3$
$∴ 3$ moles of $H_{2} S O_{4} = 294 g$
(ii) No. of molecules in $3$ moles of $H_{2} S O_{4} = 3 \times 6.023 \times 10^{23}$
$= 18.069 \times 10^{23}$

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Calculate (i) the number of moles (ii) the number of molecules in 294 g of sulphuric acid. [S=32, H=1, O=16]

Gram molecular weight of H2SO4=98gGiven weight= 294g(i) No. of moles= Given weightGram molecular weight=29498=3∴3 moles of H2SO4=294g(ii) No. of molecules in 3 moles of H2SO4=3×6.023×1023 =18.069×1023

Calculate (i) the number of moles (ii) the number of molecules in 294 g of sulphuric acid.
[ $S = 32, H = 1, O = 16$ ]