Calculate, in Pa, pressure due to 0.76 m of mercury column. Density of mercury = $13600 k g m^{- 3}$ , $g = 9.8 m s^{- 2}$ .

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Solution

Step 1: Given data,
Height of mercury column is $h = 0.76 m$ .
Density of mercury is $d = 13600 k g m^{- 3}$ .
Acceleration due to gravity is $a = g = 9.8 m s^{- 2}$ .
Pressure is $P = ?$
Step 2: Finding the pressure due to mercury column,
We know, $P = h d g$
$\Rightarrow P = 0.76 \times 13600 \times 9.8 \Rightarrow P = 101292.8$
Therefore, Pressure due to mercury column is $101292.8 P a$ .

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= 13.6 g

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