Question

calculate $\int (6x^6+4x^{\frac{2}{3}}+8)dx$

Answer 1

$\int (6x^6+4x^{2/3}+8)dx$

$=\frac{6x^{6+1}}{6+1}+\frac{4x^{2/3+1}}{\frac{2}{3}+1}+8x+c$

$=\frac{6x^7}{7}+\frac{12}{5}{x}^{5/3}+8x+c$.