Question

Calculate:
$\int (x^3-\frac{1}{x}+3x)dx$.

• A. $\frac{x^4}{3}-\log x+\frac{3x^2}{2}+c$
• B. $\frac{x^4}{4}-\log x+\frac{2x^3}{2}+c$
• C. $\frac{x^4}{4}-\log x+\frac{3x^2}{4}+c$
• D. $\frac{x^4}{4}-\log x+\frac{3x^2}{2}+c$

Answer 1

The correct option is D $\frac{x^4}{4}-\log x+\frac{3x^2}{2}+c$

$\int (x^3-\frac{1}{x}+3x)dx$

$=\frac{x^4}{4}-ln|x|+\frac{3x^2}{2}+c$