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Introduction to Radial & Tangential Acceleration

Calculate its...

Question

Calculate its centripetal acceleration. (in $m / s^{2}$ )

5.941 \times 10^{- 3}

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5.941 \times 10^{- 4}

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5.941 \times 10^{- 2}

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7 \times 10^{- 3}

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Solution

The correct option is A $5.941 \times 10^{- 3}$
$ω = \frac{2 π}{p e r i o d o f o n e r e v o l u t i o n (s e c)} =$ $\frac{2 π}{365 \times 24 \times 60 \times 60} = 1.99 \times 10^{- 7} r a d / s$
As we know
$v = r ω = 1.5 \times 10^{11} \times 1.99 \times 10^{- 7} = 2.985 \times 10^{4} m / s$
Centripetal acceleration
$a_{c} = \frac{v^{2}}{r}$ = $\frac{{(2.985 \times 10^{4})}^{2}}{1.5 \times 10^{11}} = 5.941 \times 10^{- 3} m / s^{2}$

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Calculate its centripetal acceleration. (in m/s2)

The correct option is A 5.941×10−3ω=2πperiod of one revolution(sec) =2π365×24×60×60=1.99×10−7rad/sAs we know v=rω=1.5×1011×1.99×10−7=2.985×104m/sCentripetal accelerationac=v2r =(2.985×104)21.5×1011=5.941×10−3m/s2

Calculate its centripetal acceleration. (in $m / s^{2}$ )