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Salt of Weak Acid and Weak Base

Calculate: ...

Question

Calculate: $K_{a}$ for a monobasic acid whose $0.10 M$ solution has $p H$ of $4.50$ is $10^{- x}$ .
The value of $x$ is:

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Solution

$p H = \frac{1}{2} p K_{a} - \frac{1}{2} log C$
$4.50 \times 2 = p K_{a} - log (0.1) = p K_{a} + 1$

$9 - 1 = p K_{a}$

$p K_{a} = 8$

$K_{a} = 10^{- 8}$

$∴ x = 8$

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