Calculate Kc for Hg2- - Hg - Hg22- Give that Eo2Hg-Hg2- - - 0-788V and EoHg22- - 2 Hg2- - - 0-920 V-Write answer as nearest integer after dividing by 100-

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Equilibrium Constant from Nernst Equation

Calculate K...

Question

Calculate $K_{c}$ for $H g^{2 +} + H g ⇌ H g_{2}^{2 +}$ .
Give that $E_{2 H g / H g^{2 +}}^{o} = - 0.788 V$ and $E_{H g_{2}^{2 +} / 2 H g^{2 +}}^{o} = - 0.920 V$ .
Write answer as nearest integer after dividing by 100.

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H g^{2 +} + H g \to H g_{2}^{2 +}

E_{(H g | H g^{2 +})}^{⊖} = - 0.788 V; E_{(H g_{2}^{2 +} | 2 H g^{2 +})}^{⊖} = - 0.92 V

K_{e q} = 2.98 \times 10^{x}

x

H g_{2}^{2 +} + 2 e^{-} \to 2 H g ⟹ E^{0} = 0.789 V

H g^{2 +} + 2 e^{-} \to H g ⟹ E^{0} = 0.854 V

H g_{2}^{2 +} \to H g + H g^{2 +}

2 {F e}^{3 +} (a q) + {({H g}_{2})}^{2 +} (a q) ⇌ 2 {F e}^{2 +} (a q) + 2 {H g}^{2 +} (a q)

K_{c} = 9.14 \times 10^{- 6}

25

[{F e}^{3 +}] = 0.5 M, [{H g}_{2}^{2 +}] = 0.5 M, [{F e}^{2 +}] = 0.03 M

[{H g}^{2 +}] = 0.03 M

2 {F e}^{3 +} (a q) + {{(H g}_{2})}^{2 +} (a q) ⇌ 2 {F e}^{2 +} (a q) + {2 H g}^{2 +} (a q)

K_{C} = 9.14 \times 10^{- 6}

{F e}^{3 +} = 0.5 M

{H g}_{2}^{2 +} = 0.5 M

{F e}^{2 +} = 0.03 M

{H g}^{2 +} = 0.03 M

H g

H g^{1 +}

H g^{2 +}

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