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Question

Calculate λm for acetic acid.
λm (HCl) =426 Scm2mol1
λm (NaCl) =126 Scm2mol1
λm(CH3COONa)=91 Scm2mol1

A
420 Scm2mol1
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B
329 Scm2mol1
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C
391 Scm2mol1
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D
None of these
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Solution

The correct option is B 391 Scm2mol1
Λm CH3COOH=?

Λm (NaCl)=126 Scm2 mol1

Λm (CH3COONa)=91 Scm2 mol1

Λm (HCl)=ΛH++ΛCl=426.....(i)

Λm (NaCl)=ΛNa++ΛCl=126.....(ii)

Λm (CH3COONa)=ΛCH3COO+ΛNa+=91.....(iii)

Add equation (i) and (iii) and subtract equation (ii)

Λm(CH3COOH)=ΛHCl+ΛCH3COONaΛNaCl

=ΛCH3COO+ΛH+

ΛmCH3COOH=426+91126
=391 Scm2mol1

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