Calculate 3xx-5-64x-20- given that x- -5

The correct option is B 2x ( 3xx + 5 #160; ) ÷ ( 64x + 20 ) = ( 3xx + 5 ) × ( 4x + 206 ) = ( x × 4 (x + 5)(x + 5) × 2 ) = ( 2x ) ...

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Byju's Answer

Standard XII

Mathematics

Properties of Composite Function

Calculate 3...

Question

Calculate $(\frac{3 x}{x + 5}) \div (\frac{6}{4 x + 20})$ , given that $x \neq - 5$

2 x

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\frac{x}{2}

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\frac{9 x}{2}

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2 x + 4

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Solution

The correct option is B $2 x$
$(\frac{3 x}{x + 5}) \div (\frac{6}{4 x + 20})$
$= (\frac{3 x}{x + 5}) \times (\frac{4 x + 20}{6})$
$= (\frac{x \times 4 (x + 5)}{(x + 5) \times 2})$
$= (2 x)$

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Similar questions

Q. Solve :

\int \frac{x^{6} - 2 x^{4} + 3 x^{3} - 9 x^{2} + 4}{x^{5} - 5 x^{3} + 4 x} d x

Q. The total possible no. of roots of the equation

4 x^{7} + 3 x^{6} + 2 x^{5} + 9 x^{4} + 4 x^{3} + x^{2} + 9 x + 9 = 0

Solve :

$(i) \frac{1}{3} x - 6 = \frac{5}{2} (i i) \frac{2 x}{3} - \frac{3 x}{8} = \frac{7}{12} (i i i) (x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0 (i v) \frac{1}{10} - \frac{7}{x} = 35 (v) 13 (x - 4) - 3 (x - 9) - 4 (x + 4) = 0 (v i) x + 7 - \frac{8 x}{3} = \frac{17 x}{6} - \frac{5 x}{8} (v i i) \frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x (v i i i) \frac{x + 2}{6} - (\frac{11 - x}{3} - \frac{1}{4}) = \frac{3 x - 4}{12} (i x) \frac{2}{5 x} - \frac{5}{3 x} = \frac{1}{15} (x) \frac{x + 2}{3} - \frac{x + 1}{5} = \frac{x - 3}{4} - 1 (x i) \frac{3 x - 2}{3} + \frac{2 x + 3}{2} = x + \frac{7}{6} (x i i) x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3} (x i i i) \frac{9 x + 7}{2} - (x - \frac{x - 2}{7}) = 36 (x i v) \frac{6 x + 1}{2} + 1 = \frac{7 x - 3}{3}$

\int_{- 2}^{2} \frac{3 x^{5} + 4 x^{3} + 2 x^{2} + x + 20}{x^{2} + 4} d x = ?

Which of these statements hold true?

i.) $4 (x - 5) = 4 x - 5$

ii.) $x (3 x + 2) = 3 x^{2} + 2$

iii.) $2 x^{2} + 4 (2 x) + 7 = 2 x^{2} + 8 x + 7$ [4 MARKS]

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Calculate (3xx+5)÷(64x+20), given that x≠−5

The correct option is B 2x(3xx+5)÷(64x+20)=(3xx+5)×(4x+206)=(x×4(x+5)(x+5)×2)=(2x)

Calculate $(\frac{3 x}{x + 5}) \div (\frac{6}{4 x + 20})$ , given that $x \neq - 5$

The correct option is B $2 x$
$(\frac{3 x}{x + 5}) \div (\frac{6}{4 x + 20})$
$= (\frac{3 x}{x + 5}) \times (\frac{4 x + 20}{6})$
$= (\frac{x \times 4 (x + 5)}{(x + 5) \times 2})$
$= (2 x)$