Question

Calculate magnetic flux density of the magnetic field at the centre of a circular coil of $50$ tunrs, having radius of $0.5$m and carrying a current of $5$A.

Answer 1

Given

$n=50turns$, $R=0.5m$, $I=5A$,

According to Bio-sawart Law

magnetic flux density is given by $B$

$\Rightarrow B=\frac{{\mu }_{0}nI}{2R}$

$\Rightarrow B=\frac{4\pi \times {10}^{-7}\times 50\times 5}{2\times 0.5}=3.14\times {10}^{-3}T$