Question

Calculate maximum number of electrons in ${}_{25}Mn$ which have n=3, m=0 and s= =1/2.

Answer 1

$n=3$ are present for $s,m=0$

$p,m=+1,0,-1$

$d,m=+2,+1,0,-1,-2$

So $m=0,6$ electrons are present where half are $s=\frac{+1}{2}$ and other $s=\frac{-1}{2}$

Hence, only $3$ electrons have $n=3,m=0,s=\frac{+1}{2}$