Question

Calculate maxium number of electrons in ${}_{25}Mn$ which have $n=3,m=0$ and $s=+\frac{1}{2}$.

Answer 1

Mn

Atomic number = 25

Electronic configuration: $1S^{2}2S^{2}2P^{6}3S^{2}3P^{6}4S^{2}3d^5$

'n' is the principal quantum number, represents the energy level of the electron.

'l' is the azimuthal quantam number, describes the orbital angular momentum and the shape of the orbital, ranges from 0 to (n-1).

'm' is the magnetic quantum number distinguishes the orbitals available within a subshell, and is used to calculate the orientation of orbital in space, ranges from -l to +l.

's' is the spin quantum number which completely describe the quantum state of an electron. $\frac{-1}{2};\frac{+1}{2}$