Calculate mean and standard deviation :
Class Interval0−1010−2020−3030−4040−50Frequency8131685
¯X=A+∑fd′′N×i=25+(−11)50×10=25−2.2=22.8
S.D.(σ)=√∑fd′2N−(∑fd′N)2×i=√7350−(−1150)2×10
=√1.46−(0.22)2×10
=√1.4116×10
=1.188×10
=11.88