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Question

Calculate mean deviation about median for following readings
Class20−4040−6060−8080−100Fi20443040


A

18.6

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B

18.7

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C

18.8

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D

18.9

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Solution

The correct option is C

18.8


We need to calculate the median first.

Class20404060608080100fi20443040c.fi206494134

Median=l+N2cfX h

Median class=(6080) class as it contains (1342)th term

l=60,N=134,f=30,h=20.

Median =60+(13426430) 20

=60+(676430)20=60+2=62

M=62

Class20404060608080100fi20443040Meandeviations|3062||5062||7062||9062|=32=12=8=28

Mean deviation about median (M) =4i14i=1fi|xiM|401fi

=20(32)+44(12)+30(8)+40(28)134

=640+528+240+1120134

=2528134=18.8


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