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Question

Calculate Median salary from the following frequency distribution:

X (Rs. in 000)10−2020−3030−4040−5050−6060−70
Y (Frequency)236522

A
38.5
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B
36.98
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C
38.33
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D
39.00
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Solution

The correct option is C 38.33
Median is the middle most value of a given series that represents the whole class of the series. For a group data,
Median = L + [{(n/2) – B}/G] × w where
  • Lis the lower class boundary of the group containing the median
  • nis the total number of values
  • Bis the cumulative frequency of the groups before the median group
  • Gis the frequency of the median group
  • wis the group width
Since the median is the middle value, which in this case is the 10th one, which is in the 30-40 group. Therefore , 30-40 is the median group so
  • L= 30
  • n= 20
  • B= 2 + 3 = 5
  • G= 6
  • w= 10

Median= 30 + [{(20/2) – 5}/6] × 10

  • = 30 + 8.33
  • = 38.33



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