Calculate mode of the following data.
Marks $0 - 20$ $20 - 40$
$40 - 60$ $60 - 80$
$80 - 100$
Number of students $8$ $10$ $12$ $6$ $3$

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Solution

Highest frequency $12$ , Modal class $= 40 - 60$
Mode $= I + \frac{f_{1} - f_{0}}{2 f_{1} - f_{0} - f_{2}} \times h$
Where ,
$I =$ lower limit of the modal class $= 40$
$f_{1} =$ frequency of modal class $= 12$
$f_{2}$ frequency of class after the modal class $= 6$
$f_{0}$ frequency of class before the modal class $= 10$
$h =$ class width $= 20$
putting the values in the equation
$M o d e = 50$

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Q. Draw a histogram and frequency polygon to represent the following data.

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No. of Students	$12$	$22$	$35$	$40$	$60$	$52$	$40$	$30$	$5$

Q. Find the mean, median and mode of the following data:

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Frequency:	$6$	$8$	$10$	$12$	$6$	$5$	$3$

Find the mean, median and mode of the following data:
$\begin{matrix} Class & 0 - 20 & 20 - 40 & 40 - 60 & 60 - 80 & 80 - 100 & 100 - 120 & 120 - 140 Frequency & 6 & 8 & 10 & 12 & 6 & 5 & 3 \end{matrix}$

Q. Find the median of the following data:

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Q. Find the mean of the following distribution.

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Calculate mode of the following data.Marks 0−20 20−4040−60 60−8080−100Number of students8101263

Calculate mode of the following data.
Marks $0 - 20$ $20 - 40$
$40 - 60$ $60 - 80$
$80 - 100$
Number of students $8$ $10$ $12$ $6$ $3$