The correct option is
A 37.5
Mode is the value which occurs the highest number of times in a series.
Mode= L + [ (fm − fm-1)/{(fm − fm-1) + (fm − fm+1)}] × w
where
- L is the lower class boundary of the modal group
- fm-1is the frequency of the group before the modal group
- fmis the frequency of the modal group
- fm+1is the frequency of the group after the modal group
- w is the group width
Therefore, in the given sum the modal class is 30-40 so - L = 30
- fm-1= 3
- fm= 6
- fm+1= 5
- w = 10
Mode = 30 + [(6 – 3)/{(6 − 3) + (6 − 5)}] × 10 = 30 + (3/4) × 10
= 37.5