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Question

Calculate Mode salary from the following frequency distribution:
X in Rs. (000)10-2020-3030-4040-5050-6060-70
Y Frequency236522

A
37.5
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B
37
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C
38.5
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D
39
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Solution

The correct option is A 37.5
Mode is the value which occurs the highest number of times in a series.
Mode= L + [ (fm − fm-1)/{(fm − fm-1) + (fm − fm+1)}] × w
where
  • L is the lower class boundary of the modal group
  • fm-1is the frequency of the group before the modal group
  • fmis the frequency of the modal group
  • fm+1is the frequency of the group after the modal group
  • w is the group width
Therefore, in the given sum the modal class is 30-40 so
  • L = 30
  • fm-1= 3
  • fm= 6
  • fm+1= 5
  • w = 10
Mode = 30 + [(6 – 3)/{(6 − 3) + (6 − 5)}] × 10
= 30 + (3/4) × 10
= 37.5

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