Calculate molecular formula of a compound is $C_{6} H_{18} O_{3 .}$ Find its empirical formula.

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Solution

Step 1: Molecular formula of a compound is $C_{6} H_{18} O_{3 .}$
Step 2: Molecular formula $= n \times (E m p i r i c a l f o r m u l a)$
Step 3: $C_{6} H_{18} O_{3}$ can be written as $3 (C_{2} H_{6} O)$
Molecular formula $= 3 \times (C_{2} H_{6} O)$
Therefore, empirical formula of a compound is $C_{2} H_{6} O .$

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Calculate molecular formula of a compound is C6H18O3. Find its empirical formula.

Step 1: Molecular formula of a compound is C6H18O3.Step 2: Molecular formula =n×EmpiricalformulaStep 3: C6H18O3 can be written as 3C2H6O Molecular formula =3×C2H6O Therefore, empirical formula of a compound is C2H6O.

Calculate molecular formula of a compound is $C_{6} H_{18} O_{3 .}$ Find its empirical formula.