Question

Calculate no. of atoms in $4$g of $H_{2}S{O}_4$.

Answer 1

Molecular weight of $H_{2}S{O}_4$ = 98 g/mol

Hence , The number of moles of $H_{2}S{O}_4=\frac{4}{98}=0.04$

the compound has 2 molecules of H, 1 molecule of S, and 4 molecules of O. So in total, there are 7 atoms in 1 molecule of $H_{2}S{O}_4$

Total atoms $=7\times 0.04\times 6.022\times {10}^{23}$

$=1.686\times {10}^{23}$