Calculate number of atoms present in 500 ml 0.05 M aqueous solution of $H_{2} S O_{4}$ ?

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Solution

$1 m o l e = 6.023 \times 10^{23}$
$M o l a r i t y = \frac{N u m b e r O f M a s s}{V o l u m e (m l)} \times 1000$
$0.05 = \frac{N u m b e r O f M o l e s}{500} \times 1000$
$N u m b e r$ $o f$ $M o l e s = 0.025$
$t o t a l$ $a t o m s$ $= 0.025 \times 6.023 \times 10^{23} a t o m s$

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