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Question

calculate number of electrons in Fe having

n+ l+M=2

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Solution

The value of n+l+m=2 can be obtained in the following combinations
  1. n=2 l=1 m=-1. This 2px orbital and there will be two electrons in this subshell
  2. n=2 l=0 m=0. This is 2s orbital and there will be two electrons in this orbital
So there are four electrons in total that will have n+l+m=2

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