Question

Calculate number of molecules in $17.6\times {10}^3$ kg of carbon dioxide.

Answer 1

No. of molecules in $17.6\times {10}^3$ of ${CO}_2$

No. of moles$=\frac{Givenmass}{GramMolecularMass}$

Gram Molecular Mass of ${CO}_2$=$12+2\times 16=12+32=44g$

$n=\frac{17.6\times {10}^3\times {10}^3}{44}g=0.4\times {10}^6=4\times {10}^{5}moles$

$1$mole contains $6.022\times {10}^{23}molecules\therefore 4\times {10}^{5}moles⟶6.022\times {10}^{23}\times 4\times {10}^5=24.088\times {10}^{28}molecules$

No. of molecules in $17.6\times {10}^{3}kg$ of ${CO}_2$ is $24.088\times {10}^{28}$molecules