Calculate number of moles in 5.6 cubic centimeter of Ammonia at STP ?

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Solution

$1$ mole of gas at STP occupies $22400$ $c m^{3}$ volume
$∴ x$ moles of gas at STP will occupy $5.6$ $c m^{3}$ volume $x = \frac{5.6 \times 1}{22400} = 2.5 \times 10^{- 4}$ moles
$∴$ moles of $N H_{3} = 2.5 \times 10^{- 4}$ moles

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Calculate number of moles in 5.6 cubic centimeter of Ammonia at STP ?

1 mole of gas at STP occupies 22400 cm3 volume∴x moles of gas at STP will occupy 5.6 cm3 volume x=5.6×122400=2.5×10−4 moles ∴ moles of NH3=2.5×10−4 moles

$1$ mole of gas at STP occupies $22400$ $c m^{3}$ volume
$∴ x$ moles of gas at STP will occupy $5.6$ $c m^{3}$ volume $x = \frac{5.6 \times 1}{22400} = 2.5 \times 10^{- 4}$ moles
$∴$ moles of $N H_{3} = 2.5 \times 10^{- 4}$ moles