Question

Calculate number of sigma $\left(\sigma \right)$ and pi $\left(\pi \right)$ bonds in the given structures.

(i) (ii)
(iii) $C{H}_2=C{\left(C{H}_{2}C{H}_{2}C{H}_3\right)}_2$
(iv)

Answer 1

(i) Lewis’s structure :
Draw the Lewis structure of given compound to visualize the number and types of bonds. Lewis’s structure of given molecular formula can be drawn as:


Identification $\sigma \&\pi$ bonds:
Identify $\sigma \&\pi$ bonds then mark it.


Count the number of $\sigma \&\pi$ bond:
${\sigma }_{C-H}=22$
${\sigma }_{C-C}=11$
$\text{Total number of sigma}\left(\sigma \right)\text{bonds}=33$
${\pi }_{C=C}=2$
$\text{Total number of pi}\left(\pi \right)\text{bonds}=2$

Final Answer: In given compound $33$ sigma $\left(\sigma \right)$ and $2$ pi $\left(\pi \right)$ bonds are present.

(ii) Lewis’s structure :
Draw the Lewis structure of given compound to visualize the number and types of bonds. Lewis’s structure of given molecular formula can be drawn as:


Identification $\sigma \&\pi$ bonds:
Identify $\sigma \&\pi$ bonds then mark it.


Count the number of $\sigma \&\pi$ bond:
${\sigma }_{C-H}=10$
${\sigma }_{C-C}=7$
$\text{Total number of sigma}\left(\sigma \right)\text{bonds}=17$
${\pi }_{C=C}=4$
$\text{Total number of pi}\left(\pi \right)\text{bonds}=4$

Final Answer : In given compound $17$ sigma $\left(\sigma \right)$ and $4$ pi $\left(\pi \right)$ bonds are present.


(iv) Lewis’s structure :
Draw the Lewis structure of given compound to visualize the number and types of bonds. Lewis’s structure of given molecular formula can be drawn as:


Identification $\sigma \&\pi$ bonds :
Identify $\sigma \&\pi$ bonds then mark it.

Count the number of $\sigma \&\pi$ bond :
${\sigma }_{C-H}=28$
${\sigma }_{C-C}=13$
$\text{Total number of sigma}\left(\sigma \right)\text{bonds}=41$
${\pi }_{C=C}=1$
$\text{Total number of pi}\left(\pi \right)\text{bonds}=1$

Final Answer: In given compound $41$ sigma $\left(\sigma \right)$ and $1$ pi $\left(\pi \right)$ bonds are present.

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