Question

Calculate number of unit cells in $58.5$ of a compound which forms $BCC$. [Molar mass of a compound $=58.5$]

Answer 1

We will apply the concept of Avogadro's constant in this question.

Avogadros constant :

1 mole = $6.022\times {10}^{23}$

The number of moles in the substance is :

Moles $=\frac{mass}{molarmass}$

Moles $=\frac{58.5}{58.5}$ = 1 moles

Number of cells $=1\times 6.022\times {10}^{23}=6.022\times {10}^{23}$