Question

Calculate order of reaction from the following data:
$2N{H}_3⟶N_2+3H_2$ (reaction)
$\begin{array}{cccc}Pressure\left(mmHg\right)& 50& 100& 200\\ Halflives\left(min\right)& 3.52& 1.82& 0.93\end{array}$

Answer 1

We know that,
$n=1+\frac{{\log }_{10}{\left(t_{1/2}\right)}_1-{\log }_{10}{\left(t_{1/2}\right)}_2}{{\log }_{10}{p}_2-{\log }_{10}{p}_1}$
$=1+\frac{{\log }_{10}3.52-{\log }_{10}1.82}{{\log }_{10}100-{\log }_{10}50}$
$=1.95\approx 2$
Similarly, we may calculate for other set of conditions.