Question

Calculate oxidation number of central atom in $\left[K_4\right[Fe\left(CN{)}_6\right]$.

Answer 1

1)Oxidation state of Fe in$K_4\left[Fe\right(CN{)}_6=+2$.

2)The name of this complex salt is Potassium ferrocyanide.( Or) Potassium Hexa cyano Ferrate(II).

$4\left(K\right)+Fe+6\left(CN\right)=0$

To calculate the OXIDATION-NUMBER of $Fe:+4+Fe+6(-1)=0$

So $Fe=+6–4=2$