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Question

Calculate oxidation number of S in Na2S2O3 & Na2S4O6 respectively.

A
-2, -2.5
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B
+2.5, +2
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C
+2, +2.5
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D
+2, +1
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Solution

The correct option is C +2, +2.5
charge on oxygen atom is =-2
charge on sodium atom is =+1
(i) Let oxidation number of S-atom in Na2S2O3 is x.
(+1)×2+(x)×2+(2)×3=0
x=+2
(ii) Let oxidation number of S-atom in Na2S4O6 is x
(+1)×2+(x)×4+(2)×6=0x=+2.5

It is important to note here that Na2S2O3 have two S-atoms and there are four S-atoms in Na2S4O6. However none of the sulphur atoms in both the compounds have +2 or + 2.5 oxidation number, it is the average of oxidation number, which reside on each sulphur atom.

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