Calculate oxidation state of:
$C r$ in $K_{2} C r_{2} O_{7}$
$S$ in $H_{2} S O_{4}$
$M n$ in $K M n O_{4}$

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Solution

A. O.S of Cr is +6
B. O.S of S is +6
C. O.S of Mn is +7

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Similar questions

Oxidation state of $C r$ in $K_{2} C r_{2} O_{7}$ is

K_{2} C r_{2} O_{7}

M n

K M n O_{4}

Oxidation state of $C r$ in $K_{2} C r_{2} O_{7}$ is

M n

K M n O_{4}

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