Calculate oxidation state of Cu in Cu(NO3)2?

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Solution

The Cu(NO3)2 is an ionic compound with oxidation number “0”. Therefore we know that sum of all the oxidation number of Cu, N and O is equal to 0.

1) the charges of the elements since it is an ionic bond. Cu=+2, N=+5, O=-2.
Simply add the numbers based on the formula:

0= +2 (2(+5) + 2×3(-2))

0= +2 (+ 10 - 12)

0=0

The above proves that the charges of the elements in the ionic bond is equal to Cu=+2, N=+5, O=-2
therefore,it is the oxidation number

Thank you :)

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