Calculate perimeter of a right angled triangle whose non-hypotenuse sides are $6$ cm and $8$ cm.

18 c m

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14 c m

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24 c m

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11 c m

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Solution

The correct option is C $24 c m$
In right $△ P Q R$ , using Pythagoras theorem,
$P R^{2} = P Q^{2} + Q R^{2} = 6^{2} + 8^{2} = 36 + 64 = 100$
$P R = \sqrt{100} = 10 ㎝$
$∴$ Perimeter of $P Q R = P Q + Q R + R P = 6 + 8 + 10 = 24 c m$

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