Question

calculate potential on the axis of a ring due to charge Q uniformly distributed along the ring of radius R

Answer 1

Dear Student,


$$\begin{gathered} thepotentialisascalrquantity \\ takedqchargepotentialduetodqataxisatatthedis\tan cexfromthecenter. \\ \int dV={\int }_0^Q\frac{kdq}{\sqrt{R^2+x^2}} \\ V=\frac{kQ}{\sqrt{R^2+x^2}} \\ Regards \end{gathered}$$