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Ideal Gas Equation

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Question

Calculate pressure of gas whose molar mass is $29.3 g / m o l .$ having density $1.29 k g / m^{3}$ at 273 K.

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Solution

$P M = d R T$
Pressure, $P = \frac{d R T}{M}$ $[d = 1.29 k g / m^{3} = 1.29 \times 10^{- 3} g / c m^{3} = 1.29 \times 10^{- 3} g / L i t]$
$= \frac{(1.29 \times 10^{- 3}) (0.0821) (273)}{29.3}$ $[R = 0.0821 l i t a t m / m o l K; T = 273 K]$
$= 0.986 \times 10^{- 3} a t m$
$= 98.6 \times 10^{- 5} a t m$

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