Calculate q for the isothermal reversible expansion of one mole of an ideal gas from an initial volume of 12L to a final volume of 120L at constant temperature of 273K.
A
−5227J
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B
+5227J
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C
3120J
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D
Noneoftheabove
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Solution
The correct option is B+5227J For an isothermal reversible expansion: w=−2.303nRT logV2V1 =−2.303×1×8.314×273log12012=−5227.2J
From the first law: ΔU=q+w
As ΔU=0 ∴q=−w=5227.2J