Calculate q (in joules), for the reversible isothermal expansion of one mole of an ideal gas 27oC from a volume of 10 dm3 to a volume of 20dm3.
A
1729 J
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B
1504 J
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C
1432 J
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D
1830 J
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Solution
The correct option is A 1729 J work is given as w=−2.303nRTlogV2V1
Given : V1=10L V2=20L T=27oC = 27+273=300K
so, w=−1×8.314×300×2.303log2010 w=−1729J
since process is isothermal △U=0
from first law of thermodynamic, △U=q+w q=−w q=1729J