Calculate quartile deviation for the following data:
Age $3$ $6$ $9$ $12$ $15$
No. of children $4$ $8$ $11$ $7$ $12$

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Solution

Age

3

6

9

12

15

Frequency

4

8

11

7

12

CF

4

12

23

30

42

$Q_{1} =$ Value of ${(\frac{n + 1}{4})}^{t h}$ term $= {10.75}^{n d}$ term $= 6$

$Q_{3} =$ Value of ${(\frac{3 n + 3}{4})}^{t h}$ term $= {32.25}^{t h}$ Term $= 15$

$Q . D = \frac{Q_{3} - Q_{1}}{2} = \frac{15 - 6}{5} = 4.5$

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