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Question

Calculate reduction potential of hydrogen electrode at 298K which is prepared with the help of aqueous solution of acetic acid with 0.1M conc at 1 atm pressure Ka= 1.8×108.

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Solution

CH3COOHCH3COO+H+
at t=0 C - -
after Eqbm CCα Cα Cα
Ka=[Cα][α][CCα]=Cα2[1α]
as CH3COOH is a weak acid, thus α<<<1
1α1
Ka=Cα2
α=KaC
[H+]=Cα=C×KaC=Ka×C
[H+]=1.8×108×0.1M
[H+]=4.24×105M
For hydrogen electrode, the cell reaction is
H++e1/2H2
Ecell=Eocell0.05911log1[H+]
as Eocell for H++C1/2H2 is zero.
Ecell=0.0591log1[H+]
Ecell=0.0591log14.24×105
Ecell=0.258V
This is the reduction potential of the Hydrogen electrode.

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